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(PHP 5, PHP 7, PHP 8)
mysqli::real_escape_string -- mysqli_real_escape_string — Escapes special characters in a string for use in an SQL statement, taking into account the current charset of the connection
Об'єктно-орієнтований стиль
Процедурний стиль
This function is used to create a legal SQL string that you can use in an SQL statement. The given string is encoded to produce an escaped SQL string, taking into account the current character set of the connection.
The character set must be set either at the server level, or with the API function mysqli_set_charset() for it to affect mysqli_real_escape_string(). See the concepts section on character sets for more information.
mysql
Тільки процедурний стиль: об'єкт mysqli, якого повертає функція mysqli_connect() або mysqli_init()
string
The string to be escaped.
Characters encoded are NUL (ASCII 0)
,
\n
, \r
, \
,
'
, "
, and
CTRL+Z.
Returns an escaped string.
Приклад #1 mysqli::real_escape_string() example
Об'єктно-орієнтований стиль
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$city = "'s-Hertogenbosch";
/* this query with escaped $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'",
$mysqli->real_escape_string($city));
$result = $mysqli->query($query);
printf("Select returned %d rows.\n", $result->num_rows);
/* this query will fail, because we didn't escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = $mysqli->query($query);
Процедурний стиль
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");
$city = "'s-Hertogenbosch";
/* this query with escaped $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'",
mysqli_real_escape_string($mysqli, $city));
$result = mysqli_query($mysqli, $query);
printf("Select returned %d rows.\n", mysqli_num_rows($result));
/* this query will fail, because we didn't escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = mysqli_query($mysqli, $query);
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Select returned 1 rows. Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's-Hertogenbosch'' at line 1 in...